In the given circuit, the voltage across the voltage across the load is maintained at 12V. The current in the zener diode varies from 0-50 mA. What is the maximum watage of the diode? 
The voltage drop across the diode and the load are same because they are connected in parallel. The maximum current through the diode is 50mA. Thus, the maximum power dissipated in the diode will be 50mA times 12V = 0.6W
In the given circuit if breakdown voltage of zener diode is 3 volt, then power of zener diode is:
The reverse breakdown voltage of a Zener diode is 5.6 V in the given circuit.
The current IZ through the Zener is
Figure shows a DC voltage regulator circuit, with a Zener diode of breakdown voltage =6 V. If the unregulated input voltage varies between 10 V to 16 V, then what is the maximum Zener current ?
A zener diode having zener voltage 8 V and power dissipation rating of 0.5 W is connected across a potential divider arranged with maximum potential drop across zener diode is as shown in the diagram. The value of protective resistance Rp is ______Ī©.
In the voltage regulator circuit shown below, the maximum load current IL that can be drawn by the load when the zener diode is biased in breakdown region is equal to ___ mA.
(Assume the minimum current to turn on the diode is Iz(min)=1mA)