In the given circuit, the voltage across the voltage across the load is maintained at 12V. The current in the zener diode varies from 0-50 mA. What is the maximum watage of the diode?
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The voltage drop across the diode and the load are same because they are connected in parallel.
The maximum current through the diode is 50mA.
Thus, the maximum power dissipated in the diode will be 50mA times 12V = 0.6W
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