In the given expression 312.22+522.32+732.42+942.52+1152.62+1362.72+1572.82+1782.92+1992.102=99x. Find the value of x
Given exp. = (1−122)+(12−132)+(13−14)+(14−15)+(152−162)+(162−172)+
(172−182)+(182−192)+(192−1102)
= 1 - 1102=1−1100=99100
The value is 100