In the given figure- AB- AC -Then AD does not bisects angle A -TrueFalse

Question

In the given figure-  AB- AC -Then AD  does not bisects angle  A -TrueFalse

Toppr Admin · Accepted Answer

In triangle ABC- since AB - ACthus- -x2220-ABC-x2220-ACB -I-xA0-angles opposite to equal sides are equal-Now- in triangles DPB and DQC-x2220-P-x2220-Q-90 -Given-x2220-ABC-x2220-ACB -From I-BD-DC -Given-Thus triangles- DPB-x2245-DQC -ASA Congruency-Hence- DP-DQ

In the given figure, $A B = A C$ .
Then $A D$ does not bisects angle $A$ .

True
False

In triangle ABC, since AB = AC
thus, $∠ A B C = ∠ A C B$ (I) (angles opposite to equal sides are equal)
Now, in triangles DPB and DQC
$∠ P = ∠ Q = 90$ (Given)
$∠ A B C = ∠ A C B$ (From I)
$B D = D C$ (Given)
Thus triangles, $D P B ≅ D Q C$ (ASA Congruency)
Hence, $D P = D Q$

In the given figure, AB=AC.Then AD does not bisects angle A.TrueFalse

In triangle ABC, since AB = ACthus, ∠ABC=∠ACB (I) (angles opposite to equal sides are equal)Now, in triangles DPB and DQC∠P=∠Q=90 (Given)∠ABC=∠ACB (From I)BD=DC (Given)Thus triangles, DPB≅DQC (ASA Congruency)Hence, DP=DQ

In the given figure, $A B = A C$ .
Then $A D$ does not bisects angle $A$ .

True
False

In triangle ABC, since AB = AC
thus, $∠ A B C = ∠ A C B$ (I) (angles opposite to equal sides are equal)
Now, in triangles DPB and DQC
$∠ P = ∠ Q = 90$ (Given)
$∠ A B C = ∠ A C B$ (From I)
$B D = D C$ (Given)
Thus triangles, $D P B ≅ D Q C$ (ASA Congruency)
Hence, $D P = D Q$