In the given figure AB-BD and angle BAC-angle DAC- Is triangle ABCequiv triangle ADC-If so- state the other pairs of corresponding parts-

Question

Toppr Admin · Accepted Answer

In -x25B3-ABC and -x25B3-ADC- AC is common-x2220-BAC-x2220-DAC -Given-AB-AD -given-x2234-x25B3-ABC-x2261-x25B3-ADCSo- the remaining pairs of corresponding parts areBC-DC- -x2220-ABC-x2220-ADC-x2220-ACB-x2220-ACD -by c-p-c-t-c-

In the given figure $A B = B D$ and $∠ B A C = ∠ D A C$ . Is $△ A B C \equiv △ A D C$ ?
If so, state the other pairs of corresponding parts.

In $△ A B C$ and $△ A D C$ , $A C$ is common.
$∠ B A C = ∠ D A C$ (Given)
$A B = A D$ (given)
$∴ △ A B C \equiv △ A D C$
So, the remaining pairs of corresponding parts are
$B C = D C$ , $∠ A B C = ∠ A D C, ∠ A C B = ∠ A C D$ (by c.p.c.t.c)

In the given figure AB=BD and ∠BAC=∠DAC. Is △ABC≡△ADC?If so, state the other pairs of corresponding parts.

In △ABC and △ADC, AC is common.∠BAC=∠DAC (Given)AB=AD (given)∴△ABC≡△ADCSo, the remaining pairs of corresponding parts areBC=DC, ∠ABC=∠ADC,∠ACB=∠ACD (by c.p.c.t.c)

In the given figure $A B = B D$ and $∠ B A C = ∠ D A C$ . Is $△ A B C \equiv △ A D C$ ?
If so, state the other pairs of corresponding parts.

In $△ A B C$ and $△ A D C$ , $A C$ is common.
$∠ B A C = ∠ D A C$ (Given)
$A B = A D$ (given)
$∴ △ A B C \equiv △ A D C$
So, the remaining pairs of corresponding parts are
$B C = D C$ , $∠ A B C = ∠ A D C, ∠ A C B = ∠ A C D$ (by c.p.c.t.c)