0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure ABC is a triangle and GHED is a rectangle $$BC = 12$$ cm, $$HE = 6$$ cm, $$FC = BF$$ and altitude $$AF$$ is $$24$$ cm. The area of the rectangle is ______

A
$$\displaystyle 56cm^{2}$$
B
$$\displaystyle 54cm^{2}$$
C
$$\displaystyle 60cm^{2}$$
D
$$\displaystyle 72cm^{2}$$
Solution
Verified by Toppr

Correct option is B. $$\displaystyle 54cm^{2}$$

Was this answer helpful?
0
Similar Questions
Q1
In the given figure (not drawn to scale), ABCD is a rectangle. ED = 16 cm, FG = FC = 8 cm, BF = 20 cm and FG is perpendicular to BC. If CD is half of AD, then find the area of the blue region (in cm2).

View Solution
Q2
In the given figure, ABC is a right triangle right-angled at B, EF  ⊥  BC. If AF  =  3 cm, AB = 21cm and FC = 4 cm, then EF is equal to


View Solution
Q3

In the given figure, AB is parallel to DC and the area of rectangle PQRS is 42 cm2. Also, AD = BC = 17 cm.

What is the length of DC?


View Solution
Q4
If the base BC = 6 cm and the altitude AP = 4 cm, then the area of the triangle ABC = .
View Solution
Q5
The figure formed by joining the midpoints of the adjacent sides of a rectangle of sides 8 cm and 6 cm is a
(a) rectangle of area 24 cm2
(b) square of area 24 cm2
(c) trapezium of area 24 cm2
(d) rhombus of area 24 cm2
View Solution