In the given figure- ABCD is a rhombus in which AC- AB- then angle ABC equals to -

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Toppr Admin · Accepted Answer

Since ABCD is a Rhombus then-xA0-AB-BC-CD-DABut we have AC-ABTherefore- we get AC-BCThat is AB-BC-AC-x21D2- -x394-ABC is a equilateral triangle-Therefore -x2220-ABC-x2220-BCD-x2220-BAC-60-xB0-Hence -x2220-ABC-60-x2218-

In the given figure, ABCD is a rhombus in which AC $=$ AB, then $∠ A B C$ equals to :

Since $A B C D$ is a Rhombus then $A B = B C = C D = D A$

But we have $A C = A B$

Therefore, we get $A C = B C$

That is $A B = B C = A C$

$\Rightarrow$ $Δ A B C$ is a equilateral triangle.

Therefore $∠ A B C = ∠ B C D = ∠ B A C = 60 °$

Hence $∠ A B C = 60^{\circ}$

In the given figure, ABCD is a rhombus in which AC= AB, then ∠ABC equals to :

Since ABCD is a Rhombus then AB=BC=CD=DABut we have AC=ABTherefore, we get AC=BCThat is AB=BC=AC⇒ ΔABC is a equilateral triangle.Therefore ∠ABC=∠BCD=∠BAC=60°Hence ∠ABC=60∘

In the given figure, ABCD is a rhombus in which AC $=$ AB, then $∠ A B C$ equals to :

Since $A B C D$ is a Rhombus then $A B = B C = C D = D A$

But we have $A C = A B$

Therefore, we get $A C = B C$

That is $A B = B C = A C$

$\Rightarrow$ $Δ A B C$ is a equilateral triangle.

Therefore $∠ A B C = ∠ B C D = ∠ B A C = 60 °$

Hence $∠ A B C = 60^{\circ}$