In the given figure- AD- BF and CE are medians of a triangle ABC and O is a point of concurrency of medians- If AD-6 cm- then OD is equal to2 cm3 cm4 cmdfrac -2-3- cm

Question

Toppr Admin · Accepted Answer

O is centroid of -x25B3-ABC-x21D2-AOOD-212OD-AO-x2212-x2212-x2212-1AO-AO-ODAO-OD-2-1-x21D2-AD3-63-2cm

In the given figure, $A D, B F$ and $C E$ are medians of a triangle $A B C$ and $O$ is a point of concurrency of medians. If $A D = 6$ cm, then $O D$ is equal to

$2$ cm
$3$ cm
$4$ cm
$\frac{2}{3}$ cm

$O$ is centroid of $△ A B C$
$\Rightarrow \frac{A O}{O D} = \frac{2}{1}$
$2 O D = A O - - - 1$
$A O = A O + O D$
$A O = O D (2 + 1)$
$\Rightarrow \frac{A D}{3} = \frac{6}{3} = 2 c m$

In the given figure, AD,BF and CE are medians of a triangle ABC and O is a point of concurrency of medians. If AD=6 cm, then OD is equal to2 cm3 cm4 cm23 cm

O is centroid of △ABC⇒AOOD=212OD=AO−−−1AO=AO+ODAO=OD(2+1)⇒AD3=63=2cm

In the given figure, $A D, B F$ and $C E$ are medians of a triangle $A B C$ and $O$ is a point of concurrency of medians. If $A D = 6$ cm, then $O D$ is equal to

$2$ cm
$3$ cm
$4$ cm
$\frac{2}{3}$ cm

$O$ is centroid of $△ A B C$
$\Rightarrow \frac{A O}{O D} = \frac{2}{1}$
$2 O D = A O - - - 1$
$A O = A O + O D$
$A O = O D (2 + 1)$
$\Rightarrow \frac{A D}{3} = \frac{6}{3} = 2 c m$