In the given figure- BCparallel DE- area -triangle ABC-25 -cm-2-area -trap- BCED-24 -cm-2- and DE-14 cm- Calculate the length of BC-20cm10cm5cmNone of these

Question

Toppr Admin · Accepted Answer

Given- BC-x2225-DEIn -x25B3-ABC and -x25B3-ADE-x2220-BAC-x2220-DAE -Common angle-x2220-ABC-x2220-ADE -Corresponding angles-x2220-ACB-x2220-AED -Corresponding angles-Thus- -x25B3-ABC-x223C-x25B3-ADE -AAA rule-

In the given figure, $B C ∥ D E$ , area $(△ A B C) = 25 {c m}^{2}$ ,
area (trap. $B C E D) = 24 {c m}^{2}$ and $D E = 14 c m$ . Calculate the length of $B C$ .

$20 c m$
$10 c m$
$5 c m$
$N o n e o f t h e s e$

Given: $B C ∥ D E$
In $△ A B C$ and $△ A D E$
$∠ B A C = ∠ D A E$ (Common angle)
$∠ A B C = ∠ A D E$ (Corresponding angles)
$∠ A C B = ∠ A E D$ (Corresponding angles)
Thus, $△ A B C \sim △ A D E$ (AAA rule)

In the given figure, BC∥DE, area (△ABC)=25 cm2,area (trap. BCED)=24 cm2 and DE=14 cm. Calculate the length of BC.20cm10cm5cmNone of these

Given: BC∥DEIn △ABC and △ADE∠BAC=∠DAE (Common angle)∠ABC=∠ADE (Corresponding angles)∠ACB=∠AED (Corresponding angles)Thus, △ABC∼△ADE (AAA rule)

In the given figure, $B C ∥ D E$ , area $(△ A B C) = 25 {c m}^{2}$ ,
area (trap. $B C E D) = 24 {c m}^{2}$ and $D E = 14 c m$ . Calculate the length of $B C$ .

$20 c m$
$10 c m$
$5 c m$
$N o n e o f t h e s e$

Given: $B C ∥ D E$
In $△ A B C$ and $△ A D E$
$∠ B A C = ∠ D A E$ (Common angle)
$∠ A B C = ∠ A D E$ (Corresponding angles)
$∠ A C B = ∠ A E D$ (Corresponding angles)
Thus, $△ A B C \sim △ A D E$ (AAA rule)