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Question

In the given figure, $D E ∥ B C, A D = 2 c m, D B = 3 c m$ and $A E = 1.6 c m$ . Then EC is equal to

2.4 cm
1.2 cm
4.8 cm
2.5 cm

A

1.2 cm

B

2.5 cm

C

2.4 cm

D

4.8 cm

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Solution

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In the given figure,
$D E | | B C$
$A D = 2 c m, D B = 3 c m, A E = 1.6 c m$

We know that
$\frac{A D}{D E} = \frac{A E}{E C}$
$\frac{2}{3} = \frac{1.6}{E C}$
$E C = \frac{1.6 \times 3}{2}$
$E C = 2.4 c m$

Hence, this is the answer.

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