In the given figure, EF || AD and ED || AC. if BF = 4 cm, FD = 6 cm and BE = 8 cm, then BC = _______
12 cm
15 cm
25 cm
None
A
25 cm
B
12 cm
C
15 cm
D
None
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Solution
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In Δ BDA we have EF || AD ∴BDFD=BEEA⇒46=8EA ⇒EA=12cm in Δ ABC we have ED|| AC ∴BDBC=BEBA⇒BF+FDBC=BEBE+EA ⇒4+6BC=88+12 ⇒BC=10×208=25cm
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