In the given figure- AB - AD and CB - CD- thentriangle ABC cong triangle ADCAll of theseangle BCA - angle DCAangle ADC - angle ABC

Question

In the given figure- AB - AD and CB - CD- thentriangle ABC cong triangle ADCAll of theseangle BCA -  angle DCAangle ADC - angle ABC

Toppr Admin · Accepted Answer

In -x25B3- ABC and -x25B3- ADC- we haveAB-AD-xA0- -xA0- -xA0-given-CB-CD-xA0- -xA0- -given-AC-AC-xA0- -xA0-common-x2234-xA0- -x25B3- ABC -x2245- -x25B3- ADC-xA0- -xA0- -By SSS-x2234- -x2220- ADC- -x2220- ABC and -x2220- BCA- -x2220- DCA-xA0- -xA0- -xA0- -xA0-By CPCT-

In the given figure, if $A B = A D$ and $C B = C D$ , then

$△$ $A B C$ $≅$ $△$ $A D C$
All of these
$∠$ $B C A =$ $∠$ $D C A$
$∠$ $A D C =$ $∠$ $A B C$

In $△$ $A B C$ and $△$ $A D C$ , we have
$A B = A D$ (given)
$C B = C D$ (given)
$A C = A C$ (common)
$∴$ $△$ $A B C$ $≅$ $△$ $A D C$ (By SSS)
$∴$ $∠$ $A D C =$ $∠$ $A B C$ and $∠$ $B C A =$ $∠$ $D C A$ (By CPCT)

In the given figure, if AB=AD and CB=CD, then△ ABC ≅ △ ADCAll of these∠ BCA= ∠ DCA∠ ADC= ∠ ABC

In △ ABC and △ ADC, we haveAB=AD (given)CB=CD (given)AC=AC (common)∴ △ ABC ≅ △ ADC (By SSS)∴ ∠ ADC= ∠ ABC and ∠ BCA= ∠ DCA (By CPCT)

In the given figure, if $A B = A D$ and $C B = C D$ , then

$△$ $A B C$ $≅$ $△$ $A D C$
All of these
$∠$ $B C A =$ $∠$ $D C A$
$∠$ $A D C =$ $∠$ $A B C$

In $△$ $A B C$ and $△$ $A D C$ , we have
$A B = A D$ (given)
$C B = C D$ (given)
$A C = A C$ (common)
$∴$ $△$ $A B C$ $≅$ $△$ $A D C$ (By SSS)
$∴$ $∠$ $A D C =$ $∠$ $A B C$ and $∠$ $B C A =$ $∠$ $D C A$ (By CPCT)