In the given figure- AB - DC- angle ABD - angle CDB- which congruence rule would you apply to prove Delta ABD - Delta CDB -RHSSASASASSS

Question

Toppr Admin · Accepted Answer

In -x25B3-ABD and -x25B3-CDBAB-CD-xA0- -given-x2220-ABD-x2220-CDB -given-BD-DB-xA0- -common side-x2234-x25B3-ADB-x2245-x25B3-CDB by SAS criteria-So option A is correct-

In the given figure, if AB = DC, $∠ A B D = ∠ C D B$ , which congruence rule would you apply to prove $Δ A B D = Δ C D B$ ?

RHS
SAS
ASA
SSS

In $△ A B D$ and $△ C D B$
$A B = C D$ (given)
$∠ A B D = ∠ C D B$ (given)
$B D = D B$ (common side)
$∴ △ A D B ≅ △ C D B$ by $S A S$ criteria.
So option $A$ is correct.

In the given figure, if AB = DC, ∠ABD=∠CDB, which congruence rule would you apply to prove ΔABD=ΔCDB ?RHSSASASASSS

In △ABD and △CDBAB=CD (given)∠ABD=∠CDB (given)BD=DB (common side)∴△ADB≅△CDB by SAS criteria.So option A is correct.

In the given figure, if AB = DC, $∠ A B D = ∠ C D B$ , which congruence rule would you apply to prove $Δ A B D = Δ C D B$ ?

RHS
SAS
ASA
SSS

In $△ A B D$ and $△ C D B$
$A B = C D$ (given)
$∠ A B D = ∠ C D B$ (given)
$B D = D B$ (common side)
$∴ △ A D B ≅ △ C D B$ by $S A S$ criteria.
So option $A$ is correct.