In the given figure- OA-OB- OD-OC- then Delta AOD cong Delta BOC by congruence rule -SSSSASASARHS

Question

Toppr Admin · Accepted Answer

In -x25B3-AOD and -x25B3-BOCAO-BO-xA0- -given-OD-OC -given-x2220-AOD-x2220-BOC-xA0- -vertically opposite angle -x25B3-AOD-x2245-x25B3-BOC by SAS congruence rule-x394-AOD-x2245-x394-BOC

In the given figure, if $O A = O B, O D = O C$ , then $Δ A O D ≅ Δ B O C$ by congruence rule :

SSS
SAS
ASA
RHS

In $△ A O D$ and $△ B O C$
$A O = B O$ (given)
$O D = O C$ (given)
$∠ A O D = ∠ B O C$ (vertically opposite angle )
$△ A O D ≅ △ B O C$ by $S A S$ congruence rule.

In the given figure, if OA=OB,OD=OC, then ΔAOD≅ΔBOC by congruence rule :SSSSASASARHS

In △AOD and △BOCAO=BO (given)OD=OC (given)∠AOD=∠BOC (vertically opposite angle )△AOD≅△BOC by SAS congruence rule.ΔAOD≅ΔBOC

In the given figure, if $O A = O B, O D = O C$ , then $Δ A O D ≅ Δ B O C$ by congruence rule :

SSS
SAS
ASA
RHS

In $△ A O D$ and $△ B O C$
$A O = B O$ (given)
$O D = O C$ (given)
$∠ A O D = ∠ B O C$ (vertically opposite angle )
$△ A O D ≅ △ B O C$ by $S A S$ congruence rule.