In the given figure- line RT is drawn parallel to SQ- If angle QPS - 100-circ- angle PQS - 40-circ- angle PSR -85-circ- and angle QRS -70-circ- then angle QRT is45-circ-85-circ-65-circ-90-circ-

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Toppr Admin · Accepted Answer

From -x25B3-PSQ- we have-x2220-PSQ-180-x2218-x2212-100-x2218-40-40-x2218-x2234-x2220-QSR-85-x2218-x2212-x2220-PSQ-85-x2218-x2212-40-x2218-45-x2218-Since RT -x2223-x2223- SQ- therefore-x2220-TRX-45-x2218-Now- 70-x2218-x-x2218-45-x2218-180-x2218-x2234-x-x2218-180-x2218-x2212-115-x2218-65-x2218-

In the given figure, line RT is drawn parallel to SQ. If ∠QPS=100∘, ∠PQS=40∘, ∠PSR=85∘ and ∠QRS=70∘, then ∠QRT is45∘85∘65∘90∘

From △PSQ, we have∠PSQ=180∘−(100∘+40)=40∘∴∠QSR=85∘−∠PSQ=85∘−40∘=45∘Since RT ∣∣ SQ, therefore∠TRX=45∘Now, 70∘+x∘+45∘=180∘∴x∘=180∘−115∘=65∘

In the given figure, line $R T$ is drawn parallel to $S Q$ . If $∠ Q P S = 100^{\circ}$ , $∠ P Q S = 40^{\circ}$ , $∠ P S R = 85^{\circ}$ and $∠ Q R S = 70^{\circ}$ , then $∠ Q R T$ is

$45^{\circ}$
$85^{\circ}$
$65^{\circ}$
$90^{\circ}$