In the given figure, O is the centre of the circle, OA=10 cm and OC=6 cm. The length of AB is :
10 cm
8 cm
12 cm
16 cm
A
8 cm
B
10 cm
C
12 cm
D
16 cm
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Solution
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The correct option is D 16 cm
Given OA=10cm
OC=6cm
∠OCA= 90∘
By Pythagoras theorem,
AC2=OA2−OC2
=102−62
AC=8cm
We know that perpendicular from centre of circle bisects the chord
Therefore AB=2AC
AB=16cm
option D is the answer.
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Q1
In the given figure, O is the centre of the circle, OA=10 cm and OC=6 cm. The length of AB is :
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Q2
In the given figure, O is the centre of two concentric circles of radii 6 cm and 10 cm. AB is a chord of outer circle which touches the inner circle. The length of AB is
(a) 8 cm
(b) 14 cm
(c) 16 cm
(d) cm