In the given figure- PA perp AB- QB perp AB and Delta OAP cong Delta OBQ- then-OP - BQOA - OQAP - QBPA - OB

Question

Toppr Admin · Accepted Answer

It is given that-xA0-x394-OAP-xA0- -x2245-xA0- -x394-OBQ both triangles are congruent-xA0-That-is by CPCT rule- corresponding parts of congruent triangles are equal-Then-xA0-OA-OQ-AP-QB-OP-OQ- -x2220-O-x2220-O-xA0-x2220-A-x2220-B-and-xA0-x2220-P-x2220-Q-So- option B is correct-

In the given figure, $P A$ $⊥$ $A B$ , $Q B$ $⊥$ $A B$ and $Δ$ $O A P$ $≅ Δ$ $O B Q$ , then:

$O P$ $=$ $B Q$
$O A$ $=$ $O Q$
$A P$ $=$ $Q B$
$P A$ $=$ $O B$

It is given that $Δ O A P$ $≅$ $Δ O B Q$ both triangles are congruent.
That is by CPCT rule, corresponding parts of congruent triangles are equal.
Then, $O A = O Q, A P = Q B, O P = O Q$ , $∠ O = ∠ O$ , $∠ A = ∠ B$ and $∠ P = ∠ Q$ .

So, option $B$ is correct.

In the given figure, PA ⊥ AB, QB ⊥ AB and Δ OAP ≅Δ OBQ, then:OP = BQOA = OQAP = QBPA = OB

It is given that ΔOAP ≅ ΔOBQ both triangles are congruent. That is by CPCT rule, corresponding parts of congruent triangles are equal. Then, OA=OQ,AP=QB,OP=OQ, ∠O=∠O, ∠A=∠B and ∠P=∠Q.So, option B is correct.

In the given figure, $P A$ $⊥$ $A B$ , $Q B$ $⊥$ $A B$ and $Δ$ $O A P$ $≅ Δ$ $O B Q$ , then:

$O P$ $=$ $B Q$
$O A$ $=$ $O Q$
$A P$ $=$ $Q B$
$P A$ $=$ $O B$

It is given that $Δ O A P$ $≅$ $Δ O B Q$ both triangles are congruent.
That is by CPCT rule, corresponding parts of congruent triangles are equal.
Then, $O A = O Q, A P = Q B, O P = O Q$ , $∠ O = ∠ O$ , $∠ A = ∠ B$ and $∠ P = ∠ Q$ .

So, option $B$ is correct.