Solve
Guides
0
Question
In the given figure, prove that:
(i) $$\Delta \mathrm{ACB} \cong \Delta \mathrm{ECD}$$
(ii) $$\mathrm{AB}=\mathrm{ED}$$
$$\quad$$
Open in App
Solution
Verified by Toppr
Was this answer helpful?
1
Similar Questions
Q1
In the given figure , prove that
$$ \Delta ACB \cong \Delta ECD $$
$$ \Delta ACB \cong \Delta ECD $$
View Solution
Q2
In the given figure, prove that: [3 MARKS]
(i) ΔACB≅ΔECD
(ii) AB=ED
(i) ΔACB≅ΔECD
(ii) AB=ED
View Solution
Q3
In the given figure , prove that :
$$ AB = ED $$
$$ AB = ED $$
View Solution
Q4
In figure, $$EF\parallel DC\parallel AB$$. Then prove that: $$\cfrac{AE}{ED}=\cfrac{BF}{FC}$$.
View Solution
Q5
In given figure EF||AB||DC. Prove that AEED=BFFC
View Solution