The correct option is D 30o
Construction : EXTENT the point A to point G and extent point G to a point H such that PQ||AG||HB||ML
PROOF : QPA=PAG=15∘ {Alternate interior angle as QP||AG and AP transversal}
PAB=PAG+BAG
15+BAG=35∘−BAG=20∘
BAG=ABH=20∘(A.I.A as AG//BH and AB transversal)
LMB=MBH=10∘−(2) (A.I.A as BH//ML and MB tranversal)
MBA=MBH+ABH=x
From (1),(2) and (3), We Get
x=20∘+10∘ ∴x=30∘