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Question

In the given figure, the point P bisects AB and DC. Prove that ΔAPC Δ BPD.
1135434_604575f582e04f5db85f366c01a66b59.jpg

Solution
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pbisectorofABandCDPA=PBPD=PCandAPC=BOD
Hence, ΔAPCΔBDP by S.A.S criteria

1212344_1135434_ans_5cdb997d37854d70a733f0d99b1ce38b.PNG

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