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Question

In the given figure, the points A, B, C, D are concyclic, when $x = 80^{o}$ , if $z = y - 20$ then $z = ?$

$100^{o}$
$80^{o}$
$40^{o}$
$140^{o}$

A

80^{o}

B

40^{o}

C

100^{o}

D

140^{o}

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Solution

Verified by Toppr

If Quadrilateral ABCD is concyclic
Then,
Sum of opposites angles is $180$
$∴ x + y = 180$
$\Rightarrow$ $y = 180 - 80$
$\Rightarrow$ $y = 100$

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