In the graph- P and Q are two vertices of quadrilateral PQRS-Given that coordinates of R and S are -4- 2- and -1- -1- respectively- the quadrilateral PQRS is a-SquareRectangleRhombusTrapezium

Question

Toppr Admin · Accepted Answer

From the diagram we can see that quadrilateral PQRS has both diagonals equal and bisecting each other at 90-xA0-degree-Hence PQRS is a rhombus-

In the graph, P and Q are two vertices of quadrilateral PQRS.
Given that coordinates of R and S are (4, 2) and (1, -1) respectively, the quadrilateral PQRS is a.

Square
Rectangle
Rhombus
Trapezium

From the diagram we can see that quadrilateral $P Q R S$ has both diagonals equal and bisecting each other at $90$ degree.
Hence $P Q R S$ is a rhombus.

In the graph, P and Q are two vertices of quadrilateral PQRS.Given that coordinates of R and S are (4, 2) and (1, -1) respectively, the quadrilateral PQRS is a.SquareRectangleRhombusTrapezium

From the diagram we can see that quadrilateral PQRS has both diagonals equal and bisecting each other at 90 degree.Hence PQRS is a rhombus.

In the graph, P and Q are two vertices of quadrilateral PQRS.
Given that coordinates of R and S are (4, 2) and (1, -1) respectively, the quadrilateral PQRS is a.

Square
Rectangle
Rhombus
Trapezium

From the diagram we can see that quadrilateral $P Q R S$ has both diagonals equal and bisecting each other at $90$ degree.
Hence $P Q R S$ is a rhombus.