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Standard XII
Chemistry
SHE
Question
In the hydrogen atom, the energy difference between the states n=2 and n=3 is E eV. The ionisation potential of H atom is:
3.2 E
7.2 E
5.6 E
13.2 E
A
3.2 E
B
13.2 E
C
5.6 E
D
7.2 E
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Solution
Verified by Toppr
Energy difference=
E
=
E
o
[
1
(
2
)
2
−
1
(
3
)
2
]
=
5
E
o
36
⇒
E
o
=
7.2
E
Ionization potential=
E
1
=
E
o
[
1
(
1
)
2
−
1
∞
]
=
E
o
∴
E
′
=
7.2
E
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Q1
In the hydrogen atom, the energy difference between the states n=2 and n=3 is E eV. The ionisation potential of H atom is:
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Q2
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