In the molecule XeO-2-F-2- there exists one n-fold axis of symmetry and in the molecule XeO-2-F-4- the number of 2-fold axis of symmetry is m- The value of m - n is -6758

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Toppr Admin · Accepted Answer

In XeO2F2- there exists one 2-xA0-n-fold axis of symmetry- while in XeO2F4- there exists four -m- 2-fold axis of symmetry- The structures are given in the figure- Hence- n-2 and-xA0-m-4-Therefore- n-m-2-4-6

In the molecule $X e O_{2} F_{2}$ , there exists one $n$ -fold axis of symmetry and in the molecule $X e O_{2} F_{4}$ , the number of $2$ -fold axis of symmetry is $m$ . The value of $m + n$ is :
$6$
$7$
$5$
$8$

In $X e O_{2} F_{2}$ , there exists one $2 (n)$ -fold axis of symmetry, while in $X e O_{2} F_{4}$ , there exists four $(m)$ $2$ -fold axis of symmetry. The structures are given in the figure. Hence, $n = 2$ and $m = 4$ .
Therefore, $n + m = 2 + 4 = 6$

In the molecule XeO2F2, there exists one n-fold axis of symmetry and in the molecule XeO2F4, the number of 2-fold axis of symmetry is m. The value of m+n is :6758

In XeO2F2, there exists one 2 (n)-fold axis of symmetry, while in XeO2F4, there exists four (m) 2-fold axis of symmetry. The structures are given in the figure. Hence, n=2 and m=4.Therefore, n+m=2+4=6

In the molecule $X e O_{2} F_{2}$ , there exists one $n$ -fold axis of symmetry and in the molecule $X e O_{2} F_{4}$ , the number of $2$ -fold axis of symmetry is $m$ . The value of $m + n$ is :
$6$
$7$
$5$
$8$

In $X e O_{2} F_{2}$ , there exists one $2 (n)$ -fold axis of symmetry, while in $X e O_{2} F_{4}$ , there exists four $(m)$ $2$ -fold axis of symmetry. The structures are given in the figure. Hence, $n = 2$ and $m = 4$ .
Therefore, $n + m = 2 + 4 = 6$