In the presence of concentrated sulphuric acid $(H_{2} S O_{4})$ , acetic acid reacts with ethyl alcohol to produce :
aldehyde
ester
alcohol
carboxylic acid

Question

In the presence of concentrated sulphuric acid -H-2SO-4- acetic acid reacts with ethyl alcohol to produce -aldehydeesteralcoholcarboxylic acid

Toppr Admin · Accepted Answer

-xA0-CH3COOH -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0- -xA0- CH3CH2OH -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- ConcH2SO4-x2212-x2212-x2212-x2212-x2212-x2212-x2212-x2212-x2212-x2192- -xA0- -xA0-xA0-CH3COOC2H5-H2ODuring esterification- oxygen of alcohol is found in main product that is nothing but ester- This indicates that H of alcohol is eliminated as water molecule-

In the presence of concentrated sulphuric acid (H2SO4), acetic acid reacts with ethyl alcohol to produce :aldehydeesteralcoholcarboxylic acid

CH3COOH + CH3CH2OH ConcH2SO4−−−−−−−−−→ CH3COOC2H5+H2ODuring esterification, oxygen of alcohol is found in main product that is nothing but ester. This indicates that H of alcohol is eliminated as water molecule.

In the presence of concentrated sulphuric acid $(H_{2} S O_{4})$ , acetic acid reacts with ethyl alcohol to produce :
aldehyde
ester
alcohol
carboxylic acid

${C H}_{3} C O O H$ + ${C H}_{3} {C H}_{2} O H$ $C o n c H_{2} {S O}_{4} - -------- \to$ ${C H}_{3} C O O C_{2} H_{5} + H_{2} O$
During esterification, oxygen of alcohol is found in main product that is nothing but ester. This indicates that H of alcohol is eliminated as water molecule.