In the reaction 2P(g)+Q(g)⇌3R(g)+S(g). If 2 moles each of P and Q taken initially in a 1 litre flask. At equilibrium which is true?
[P]<[Q]
[P]=[Q]
[Q]=[R]
None of these
A
[P]=[Q]
B
None of these
C
[P]<[Q]
D
[Q]=[R]
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Solution
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2P(g)+Q(g)⇌3R(g)+S(g)
Initially 2moles2moles00
At eqm 2−2α2−ααα
Here 2 moles of P reacts with 1 mole of Q. So at equilibrium number of moles of P consumed will be higher than that of Q. Therefore, rate of decrease of [P] is higher than that of [Q].
∴[P]<[Q] at equilibrium.
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