In the reaction -7N-14- - -2He-4 rightarrow -8O-17- - -1H-1- The minimum energy of alpha-particle isM-N- 14-00307 amu M-He- 4-00260 amuM-o - 16-99914 amu M-H- 1-00783 amu1-21MeV1-62MeV1-96MeV1-89MeV

Question

In the reaction -7N-14- -  -2He-4 rightarrow -8O-17- -  -1H-1- The minimum energy of alpha-particle isM-N- 14-00307 amu M-He- 4-00260 amuM-o - 16-99914 amu M-H- 1-00783 amu1-21MeV1-62MeV1-96MeV1-89MeV

Toppr Admin · Accepted Answer

Mass on reactant side -14-00307-4-00260-amu

In the reaction $_{7} N^{14} +$ $_{2} H e^{4} \to_{8} O^{17} +$ $_{1} H^{1}$ . The minimum energy of $α$ -particle is
$M_{N} =$ $14.00307$ amu $M_{H e} =$ $4.00260$ amu
$M_{o} =$ $16.99914$ amu $M_{H} =$ $1.00783$ amu
$1.21 M e V$
$1.62 M e V$
$1.96 M e V$
$1.89 M e V$

Mass on reactant side $= (14.00307 + 4.00260) a m u$

In the reaction 7N14+ 2He4→8O17+ 1H1. The minimum energy of α-particle isMN= 14.00307 amu MHe= 4.00260 amuMo= 16.99914 amu MH= 1.00783 amu1.21MeV1.62MeV1.96MeV1.89MeV

Mass on reactant side =(14.00307+4.00260)amu

In the reaction $_{7} N^{14} +$ $_{2} H e^{4} \to_{8} O^{17} +$ $_{1} H^{1}$ . The minimum energy of $α$ -particle is
$M_{N} =$ $14.00307$ amu $M_{H e} =$ $4.00260$ amu
$M_{o} =$ $16.99914$ amu $M_{H} =$ $1.00783$ amu
$1.21 M e V$
$1.62 M e V$
$1.96 M e V$
$1.89 M e V$

Mass on reactant side $= (14.00307 + 4.00260) a m u$