0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

In the reaction AB (gas) = Agas +B(pas) The value of K is equal to 1/3 rd of total equilibrium pressure. What is the percentage dissociation of AB? A) 25% B) 30% C) 54 % D) 50 %

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
In the reaction AB(g)A(g)+B(g) at 30oC, Kpn for the dissociation equilibrium is 2.56×102atm. If the total pressure at equilibrium is 1 atm, then the percentage dissociation of AB is ?
View Solution
Q2
For the reaction: AB(g)A(g)+B(g),
AB is 25% dissociated at a total pressure of P. Then,
View Solution
Q3
AB3(g) is dissociated as AB3(g)AB2(g)+12B2(g).
When the initial pressure of AB2 is 800 torr and the total pressure developed at equlibrium is 900 torr. What fraction of AB3(g) is dissociated?
View Solution
Q4
At 444^Ā° C, the equilibrium constant K for the reaction 2AB gives A2 +B2,The degree of dissociation of AB will be -(A) 10%(C) 30%(B) 20(D) 50%
View Solution
Q5
For the reaction,
AB(g)A(g)+B(g),
We start with 1 mole of AB 25% of which dissociates at a total pressure of P, P is related to Kp as:
View Solution