In the reaction :- CuSO4⋅3H2O(s)⇌2CuSO4⋅H2O(s)+2H2O(v),
Dissociation pressure is 7×10−3 atm at 25 and ΔH=2700cal. If the dissociation pressure at 127 is X×10−3 atm, then 100X is__________.
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logK2K1=ΔH2.303R(1T1−1T2)) Substitute values in the above expression logK2K1=27002.303×2(1298−1400)) logK2K1=0.5 K2K1=3.16 (P7×10−3)2=3.16 P=12.46×10−3=x×10−3 x=12.46 100x=1246
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