Question

In the solar system, the Sun is in the focus of the system for Sun-earth binding system. Then the binding energy for the system will be [given that radius of the earth's orbit around the Sun is $1.5\times {10}^{11}m$ and mass of the earth = $6\times {10}^{24}kg$]

• A. $2.7\times {10}^{33}J$
• B. $5.4\times {10}^{33}J$
• C. $2.7\times {10}^{30}J$
• D. $5.4\times {10}^{30}J$

Answer 1

Answer: (A)

Binding energy $=GMm/R$
$M=$ mass of the Sun $={10}^{30}kg$
$m=$ mass of the earth $=6\times {10}^{24}kg$
$R=1.5\times {10}^{11}m$
Binding energy of the system is
$\frac{6.67\times {10}^{-11}\times {10}^{30}\times 6\times {10}^{34}}{1.5\times {10}^{11}}=2.7\times {10}^{33}J$