In the synthesis of sodium carbonate- the recovery of ammonia is done by treating NH-4-Cl with Ca-OH-2- The by-product obtained in this process is-NaHCO-3-CaCl-2-NaOHNaCl

Question

Toppr Admin · Accepted Answer

The reaction follows as-2NH4Cl-Ca-OH-2-x2192-2NH3-H2O-CaCl2

In the synthesis of sodium carbonate, the recovery of ammonia is done by treating $N H_{4} C l$ with $C a (O H)_{2}$ . The by-product obtained in this process is:
$N a H C O_{3}$
$C a C l_{2}$
$N a O H$
$N a C l$

The reaction follows as:
$2 N H_{4} C l + C a (O H)_{2} \to 2 N H_{3} + H_{2} O + C a C l_{2}$

In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH4Cl with Ca(OH)2. The by-product obtained in this process is:NaHCO3CaCl2NaOHNaCl

The reaction follows as:2NH4Cl+Ca(OH)2→2NH3+H2O+CaCl2

In the synthesis of sodium carbonate, the recovery of ammonia is done by treating $N H_{4} C l$ with $C a (O H)_{2}$ . The by-product obtained in this process is:
$N a H C O_{3}$
$C a C l_{2}$
$N a O H$
$N a C l$

The reaction follows as:
$2 N H_{4} C l + C a (O H)_{2} \to 2 N H_{3} + H_{2} O + C a C l_{2}$