In thiosulphuric acid-there is a S-S linkage present-one S atom is in -2 and other sulphur atom is in -4 oxidation state-there is only one replaceable hydrogen atom-each sulphur atom is in identical oxidation state-

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In thiosulphuric acid-xA0-there is a S-S linkage present-One S atom is in -2 and other sulphur atom is in -6 oxidation state-There are two-xA0-replaceable hydrogen atom-Option B is correct-

In thiosulphuric acid:
there is a $S = S$ linkage present.
one S atom is in +2 and other sulphur atom is in +4 oxidation state.
there is only one replaceable hydrogen atom.
each sulphur atom is in identical oxidation state.

In thiosulphuric acid there is a $S = S$ linkage present.

One S atom is in -2 and other sulphur atom is in +6 oxidation state.

There are two replaceable hydrogen atom.

Option B is correct.

In thiosulphuric acid:there is a S=S linkage present.one S atom is in +2 and other sulphur atom is in +4 oxidation state.there is only one replaceable hydrogen atom.each sulphur atom is in identical oxidation state.

In thiosulphuric acid there is a S=S linkage present.One S atom is in -2 and other sulphur atom is in +6 oxidation state.There are two replaceable hydrogen atom.Option B is correct.

In thiosulphuric acid:
there is a $S = S$ linkage present.
one S atom is in +2 and other sulphur atom is in +4 oxidation state.
there is only one replaceable hydrogen atom.
each sulphur atom is in identical oxidation state.

In thiosulphuric acid there is a $S = S$ linkage present.

One S atom is in -2 and other sulphur atom is in +6 oxidation state.

There are two replaceable hydrogen atom.

Option B is correct.