In triangle ABC- OB- OC are angular bisectors and MNparallel BC- AB-12- BC-24 and AC-18- then the perimeter of triangle AMN is30333639

Question

Toppr Admin · Accepted Answer

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In $△ A B C, O B, O C$ are angular bisectors and $M N ∥ B C$ , if $A B = 12$ , $B C = 24$ and $A C = 18$ , then the perimeter of $△ A M N$ is

$30$
$33$
$36$
$39$

$△ A M N \Rightarrow ?$
$∠ M B O = ∠ C B O = ∠ M O B = \frac{1}{2} ∠ M B C$
$A M + M N + N A = A M + M O + N O + N A$
$= A M + M B + N C + N A$
$= A B + A C = 30$

In △ABC,OB,OC are angular bisectors and MN∥BC, if AB=12, BC=24 and AC=18, then the perimeter of △AMN is30333639

△AMN⇒?∠MBO=∠CBO=∠MOB=12∠MBCAM+MN+NA=AM+MO+NO+NA =AM+MB+NC+NA =AB+AC=30

In $△ A B C, O B, O C$ are angular bisectors and $M N ∥ B C$ , if $A B = 12$ , $B C = 24$ and $A C = 18$ , then the perimeter of $△ A M N$ is

$30$
$33$
$36$
$39$

$△ A M N \Rightarrow ?$
$∠ M B O = ∠ C B O = ∠ M O B = \frac{1}{2} ∠ M B C$
$A M + M N + N A = A M + M O + N O + N A$
$= A M + M B + N C + N A$
$= A B + A C = 30$