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In △ABC,AP⊥BC,BQ⊥AC,B−P−C,A−Q−Cthenprovethat,△CPA∼△CQB.IFAP=7,BQ=&,BC=12thefindAC.
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To prove:△CPA≅△CQB
Proof:In △CPA and △CQB
∠CPA=∠CQB=90∘ (given)
∠C=∠C (common)
By AA similarity criterion,
△CPA≅△CQB
Hence proved.
Now, APBQ=ACBC since corresponding sides are proportional.
⇒AC=APBQ×BC
=78×12=10.5
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Q1
In △ABC,AP⊥BC,BQ⊥AC,B−P−C,A−Q−Cthenprovethat,△CPA∼△CQB.IFAP=7,BQ=&,BC=12thefindAC.
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Q2
In ∆ABC, AP ⊥ BC, BQ ⊥ AC B– P–C, A–Q – C then prove that, ∆CPA ~ ∆CQB. If AP = 7, BQ = 8, BC = 12 then Find AC.
