In triangles ABC and DEF- AB - FD and angle A - angle D- The two triangles will be congruent bySAS axiom -AC - DEBC - EFBC - DEAC - EF

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Toppr Admin · Accepted Answer

For triangle to be congruent by SAS axiom two of the sides and the included angle of the triangles must be equal-Given AB-DF and -x2220-A-x2220-DNo for -x25B3-ABC-x2245-x25B3-DFE-xA0- by SAS axiom we need AC-DESo option B is correct-xA0-

In triangles ABC and DEF, AB $=$ FD and $∠ A = ∠ D$ . The two triangles will be congruent by
SAS axiom if :
AC $=$ DE
BC $=$ EF
BC $=$ DE
AC $=$ EF

For triangle to be congruent by $S A S$ axiom two of the sides and the included angle of the triangles must be equal.
Given $A B = D F$ and $∠ A = ∠ D$

No for $△ A B C ≅ △ D F E$ by $S A S$ axiom we need $A C = D E$
So option $B$ is correct.

In triangles ABC and DEF, AB = FD and ∠A=∠D. The two triangles will be congruent bySAS axiom if :AC = DEBC = EFBC = DEAC = EF

For triangle to be congruent by SAS axiom two of the sides and the included angle of the triangles must be equal.Given AB=DF and ∠A=∠DNo for △ABC≅△DFE by SAS axiom we need AC=DESo option B is correct.

In triangles ABC and DEF, AB $=$ FD and $∠ A = ∠ D$ . The two triangles will be congruent by
SAS axiom if :
AC $=$ DE
BC $=$ EF
BC $=$ DE
AC $=$ EF

For triangle to be congruent by $S A S$ axiom two of the sides and the included angle of the triangles must be equal.
Given $A B = D F$ and $∠ A = ∠ D$

No for $△ A B C ≅ △ D F E$ by $S A S$ axiom we need $A C = D E$
So option $B$ is correct.