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let $y$ be the amount of second alloy mixed

Copper in $1_{st}$ alloy $=75 x$

Copper in $2_{nd}$ alloy $=73 x$

Total copper $=75x+3y $

Zinc in $1_{st}$ alloy $=72 x$

Zinc in $2_{nd}$ alloy $=74 x$

Total Zinc $=72x+4y $

Both copper & zinc should be in $∣:∣$ ratio $72x+4y 75x+3y =1$

$5x+3y=2x+4y$

$3x=y$ $⟶(I)$

we know both alloy should make $28kg$

$x+y=28$ $⟶(II)$

where $y=3x$

$x+3x=28$

$x=7kg$ $⟶1_{st}$ alloy

$y=21kg$ $⟶2_{nd}$ alloy

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