In what ratio must a grocer mix two varieties of tea worth Rs. $60$ a kg and Rs. $65$ a kg so that by selling the mixture at Rs. $68.20$ a kg he may gain $10$ %?

Question

In what ratio must a grocer mix two varieties of tea worth Rs- 60 a kg and Rs- 65 a kg so that by selling the mixture Rs- 68-20 a kg he may gain 10-4 - 53 - 43 - 23 - 5

Toppr Admin · Accepted Answer

S-P- of 1 kg of the mixture - Rs- 68-20- Gain -10-C-P- of 1 kg of the mixture - Rs- -100110-xD7-68-20- Rs- 62-By the rule of alligation- we have-x2234- Required ratio -3-2-

In what ratio must a grocer mix two varieties of tea worth Rs. $60$ a kg and Rs. $65$ a kg so that by selling the mixture at Rs. $68.20$ a kg he may gain $10$ %?
$4 : 5$
$3 : 4$
$3 : 2$
$3 : 5$

S.P. of $1$ kg of the mixture $=$ Rs. $68.20$ , Gain $= 10$ %.
C.P. of $1$ kg of the mixture $=$ Rs. $(\frac{100}{110} \times 68.20) =$ Rs. $62$ .
By the rule of alligation, we have:
$∴$ Required ratio $= 3 : 2$ .

In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?4:53:43:23:5

S.P. of 1 kg of the mixture = Rs. 68.20, Gain =10%.C.P. of 1 kg of the mixture = Rs. (100110×68.20)= Rs. 62.By the rule of alligation, we have:∴ Required ratio =3:2.

In what ratio must a grocer mix two varieties of tea worth Rs. $60$ a kg and Rs. $65$ a kg so that by selling the mixture at Rs. $68.20$ a kg he may gain $10$ %?
$4 : 5$
$3 : 4$
$3 : 2$
$3 : 5$

S.P. of $1$ kg of the mixture $=$ Rs. $68.20$ , Gain $= 10$ %.
C.P. of $1$ kg of the mixture $=$ Rs. $(\frac{100}{110} \times 68.20) =$ Rs. $62$ .
By the rule of alligation, we have:
$∴$ Required ratio $= 3 : 2$ .