In what time will it enter the hole A- sqrt-dfrac-4hR-2-GM-sqrt-dfrac-2hR-2-GM-sqrt-dfrac-hR-2-GM-None of these

Solve

Guides

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

In what time will it enter the hole at $A$ :

$\sqrt{\frac{4 h R^{2}}{G M}}$
$\sqrt{\frac{2 h R^{2}}{G M}}$
$\sqrt{\frac{h R^{2}}{G M}}$
$N o n e o f t h e s e$

\sqrt{\frac{2 h R^{2}}{G M}}

\sqrt{\frac{h R^{2}}{G M}}

N o n e o f t h e s e

\sqrt{\frac{4 h R^{2}}{G M}}

Open in App

Solution

Verified by Toppr

Was this answer helpful?

Similar Questions

20

gm of radioactive substance due to radioactive decay reduces to

10

gm in

4

minutes then in what time

80

gm of then what time

80

gm of the same substance will reduce to

10

gm?

View Solution

If 20 gm of a radioactive substance due to radioactive decay reduces to 10 gm in 4 minutes, then in what time 80 gm of the same substance will reduce to 10 gm

View Solution

20

gm of radioactive substance due to radioactive decy reduces to

10

gm in

4

minutes then in what time

80

gm of the same substance will reduce to

10

gm?

View Solution

Rashi mixed 10gm of iron with 5.8 gm of sulphur to form a compound. What will be the molecular mass of the compound produced?

View Solution

What is the mass of one Curie of

U^{234}

View Solution

In what time will it enter the hole at A:√4hR2GM√2hR2GM√hR2GMNone of these

In what time will it enter the hole at $A$ :

$\sqrt{\frac{4 h R^{2}}{G M}}$
$\sqrt{\frac{2 h R^{2}}{G M}}$
$\sqrt{\frac{h R^{2}}{G M}}$
$N o n e o f t h e s e$