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Question

In which of the following arrangements, the given sequence is not strictly according to the property indicated against it?
  1. CO2<SiO2<SnO2<PbO2; increasing oxidising power
  2. HF<HCl<HBr<HI; increasing acidic strength
  3. NH3<PH3<AsH3<SbH3; increasing acidic character
  4. H2O<H2S<H2Se<H2Te; increasing pKa values

A
CO2<SiO2<SnO2<PbO2; increasing oxidising power
B
H2O<H2S<H2Se<H2Te; increasing pKa values
C
NH3<PH3<AsH3<SbH3; increasing acidic character
D
HF<HCl<HBr<HI; increasing acidic strength
Solution
Verified by Toppr

The following sequence is not strictly according to the property indicated against it.
H2O<H2S<H2Se<H2Te; increasing pKa values.

Th correct sequence is:
H2O>H2S>H2Se>H2Te; decreasing pKa values.

In Hydrides, as we move top to bottom, acidic nature increases so with the increase in the acidity from top to bottom, the Ka value increases and pKa value decreases.

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Similar Questions
Q1
Arrange the following in order of property indicated for each set:
a. F2,Cl2,Br2,I2 - increasing bond dissociation enthalpy.
b. HF,HCl,HBr,HI - increasing acid strength.
c. NH3,PH3,AsH3,SbH3,BiH3 - increasing base strength.
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Q2

Arrange the following in the order of property indicated for each set:

F2,Cl2,Br2,I2 - increasing bond dissociation enthalpy.

HF,HCl, HBr, HI- Increasing acid strength.

NH3,PH3,AsH3,SbH3,BiH3- increasing base strength.

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Q3
Answer the following question:
Arrange the following in the order of property indicated against each set:
a. HF,HCl,HBr,HI - increasing bond dissociation enthalpy
b. H2O,H2S,H2Se,H2Te - increasing acidic character.
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Q4
Arrange the following in order of property indicated for each set.
(i) H2O,H2S,H2Se,H2Te-increasing acidic character
(ii) HF,HCl,HBr,HI -decreasing bond enthalpy
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Q5
Arrange the following in the increasing order of their basic character:
NH3,PH3,ASH3,SbH3,BiH3
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