In which of the following equilibrium- K-c-K-p- 4NH-3-g-5O-2-g-rightleftharpoons 4NO-g-6H-2O-g-N-2-g-3H-2-g-rightleftharpoons 2NH-3-g-N-2-g-O-2-g-rightleftharpoons 2NO-g-2NO-g-O-2-g- rightleftharpoons 2NO-2-g-

Question

Toppr Admin · Accepted Answer

Kp only counts with gases molecule - while Kc only counts with aqueous solution- gases- So here reactant and product both are gaseous that-apos-s why only reaction having equal numbers of reactants and products will have kp-kc ie-change in number of moles is equal to 0-option-a- is correct-xA0-

In which of the following equilibrium, $K_{c} = K_{p}$ ?
$4 N H_{3} (g) + 5 O_{2} (g) ⇌ 4 N O (g) + 6 H_{2} O (g)$
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$
$2 N O (g) + O_{2} (g) ⇌ 2 N O_{2} (g)$

Kp only counts with gases molecule , while Kc only counts with aqueous solution+ gases. So here reactant and product both are gaseous that's why only reaction having equal numbers of reactants and products will have kp=kc ie.change in number of moles is equal to 0.option(a) is correct.

In which of the following equilibrium, Kc=Kp? 4NH3(g)+5O2(g)⇌4NO(g)+6H2O(g)N2(g)+3H2(g)⇌2NH3(g)N2(g)+O2(g)⇌2NO(g)2NO(g)+O2(g)⇌2NO2(g)

Kp only counts with gases molecule , while Kc only counts with aqueous solution+ gases. So here reactant and product both are gaseous that's why only reaction having equal numbers of reactants and products will have kp=kc ie.change in number of moles is equal to 0.option(a) is correct.

In which of the following equilibrium, $K_{c} = K_{p}$ ?
$4 N H_{3} (g) + 5 O_{2} (g) ⇌ 4 N O (g) + 6 H_{2} O (g)$
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$
$2 N O (g) + O_{2} (g) ⇌ 2 N O_{2} (g)$