In which of the following, pH of acid buffer becomes equal to 3.3?
Ka=2×10−5;[salt]=0.24Mand[Acid]=0.0096M
Ka=2×10−5;[salt]=0.0096Mand[Acid]=0.24M
Ka=2×10−5;[salt]=0.24Mand[Acid]=0.48M
Ka=4×10−5;[salt]=0.0096Mand[Acid]=0.24M
A
Ka=2×10−5;[salt]=0.24Mand[Acid]=0.48M
B
Ka=4×10−5;[salt]=0.0096Mand[Acid]=0.24M
C
Ka=2×10−5;[salt]=0.24Mand[Acid]=0.0096M
D
Ka=2×10−5;[salt]=0.0096Mand[Acid]=0.24M
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Solution
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The expression for the pH of the acidic buffer solution is as given below.
pH=pKa+log[Salt][Acid]
pKa=−logKa=−log(2×10−5)=4.7.
[Salt]=0.0096M
[Acid]=0.24M.
Substitute values in the above equation.
pH=4.7+log(0.00960.24)=3.3.
Option D is correct.
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