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Updated on : 2022-09-05

Solution

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Initial Mass $=M_{0}=3.2mg$

$t_{1/2}=4m$

To calculate , mass of the substance left undecayed after $8h[M_{z}=8]$

we know,

$M_{(z)}=M_{0}e_{−λt}$

$2M_{0} =M_{0}e_{−λ(4)}$

$⇒λ=41 ln(2)$

$M_{(8)}=M_{0}.e_{−λ.8}$

$⇒M_{(8)}=M_{0}.e_{−41.ln(2).8}$

$M_{(8)}=M_{0}e_{−2ln(2)}$

$M=(4M_{0} )$

$=43.2mg $

$M_{(8)}=0.8mg$

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