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Standard XII
Mathematics
Integration by Parts
Question
∫
x
l
o
g
x
d
x
is equal to
x
2
4
(
2
l
o
g
x
−
1
)
+
c
x
2
2
(
2
l
o
g
x
+
1
)
x
2
2
(
2
l
o
g
x
−
1
)
+
c
x
2
4
(
2
l
o
g
x
+
1
)
+
c
A
x
2
2
(
2
l
o
g
x
−
1
)
+
c
B
x
2
2
(
2
l
o
g
x
+
1
)
C
x
2
4
(
2
l
o
g
x
+
1
)
+
c
D
x
2
4
(
2
l
o
g
x
−
1
)
+
c
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Solution
Verified by Toppr
Using ILATE
∫
x
I
I
l
o
g
I
x
d
x
=
l
o
g
x
⋅
x
2
2
−
∫
1
x
⋅
x
2
2
d
x
=
x
2
2
l
o
g
x
−
1
2
x
2
2
+
c
=
x
2
4
(
2
l
o
g
x
−
1
)
+
c
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Similar Questions
Q1
If
∫
x
2
−
1
(
x
2
+
1
)
√
x
4
+
1
d
x
is equal to
√
2
4
A
tan
−
1
(
1
√
2
√
x
2
+
1
/
x
2
)
+C then A is equal to.
View Solution
Q2
Solve
is equal to
(A)
(
B)
(
C)
(
D)