Internal resistance of a battery of 2volt terminal voltage is 0.2 ohm and current following through it is 0.5A.So emf of the battery will be:
1.9V
3V
2V
2.1V
A
3V
B
2V
C
2.1V
D
1.9V
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Solution
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From the figure,
The voltage drop across the internal resistance,
Vi=ir=0.5×0.2=0.1V
Emf, e=V+Vi
e=2+0.1=2.1V
The correct option is D.
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