Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

is. In the given figure, \( \angle Q > \angle R \) and \( M \) is a point on perpendicular from Pon O meets at \( \mathrm { N } \) , then prove that \( \angle \mathrm { MPN } = \frac { 1 } { 2 } ( \angle \mathrm { Q } - \angle \mathrm { R } ) \)

Open in App
Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
In the figure below, ∠Q>∠R and M is a point on QR such that PM is the bisector of ∠QPR If the perpendicular from P on QR meets QR at N then prove that ∠MPN=12(∠Q−∠R)
1086649_c1eb83758ea84e808ef2c09e9da061d4.png
View Solution
Q2
In the given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS = 12 (∠QOS − POS).
View Solution
Q3
In a ΔPQR, if PQ = QR and L, M and N are the mid-points of the sides PQ, OR, and RP respectively. Prove that LN = MN.
View Solution
Q4
In figure, two tangents RQ and RP are drawn from an external point R to the circle with centre O. If ∠PRQ=120∘, then prove that OR=PR+RQ.

View Solution
Q5
In the given figure, O is a point inside a ∆PQR such that ∠POR = 90°, OP = 6 cm and OR = 8 cm. If PQ = 24 cm and QR = 26 cm, prove that ∆PQR is right-angled.
View Solution