0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Is the function f(x)=x(ax+1)ax1 odd or even
  1. odd
  2. even
  3. neither even nor odd
  4. even for only some values of x is domain

A
even
B
neither even nor odd
C
even for only some values of x is domain
D
odd
Solution
Verified by Toppr

f(x)=x(ax+1)ax1

Was this answer helpful?
8
Similar Questions
Q1
Is the function f(x)=x(ax+1)ax1 odd or even
View Solution
Q2
Determine whether the following is even or odd
f(x)=x(ax+1ax1)
View Solution
Q3
Find whether f(x)=ax+1ax1 is even, odd or neither odd nor even.
View Solution
Q4
Find out whether the given function is even, odd or neither even nor odd, where
f(x)=x|x|,x1[1+x]+[1x],1<x<1x|x|,x1
where || and [] represent the modulus and greatest integral functions.
View Solution
Q5
Assertion :f is even, g is odd then fg(g0) is an odd function. Reason: If f(x)=f(x) for every x of its domain then f(x) is called odd function and if f(x)=f(x) for every x of its domain, then f(x) is called even function.
View Solution