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Question

Isopropyl alcohol is heated with suspension of bleaching powder (CaOCl2) with water. The products are:
  1. ethyne and ethene
  2. ethane and propane
  3. trichloromethane and calcium acetate
  4. carbon tetrachloride

A
carbon tetrachloride
B
ethyne and ethene
C
ethane and propane
D
trichloromethane and calcium acetate
Solution
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CaOCL2+H2OCl2+Ca(OH)2
Hence the answer is (c)
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