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Question

Isopropyl alcohol on oxidation forms:
ethylene
ether
acetone
acetaldehyde

A

acetone

B

ether

C

ethylene

D

acetaldehyde

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Solution

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Isopropyl alcohol forms acetone on oxidation.

The reaction is as follows:
$C H_{3} C H (O H) C H_{3} [O] - - \to H^{+} C H_{3} C O C H_{3}$

Option B is correct.

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