Question

It is given that in a group of $3$ students, the probability of $2$ students not having the same birthday is $0.992$. What is the probability that the $2$ students have the same birthday?

Answer 1

Let $\overline{B}=$ Event that $2$ students do not have same birthday

$\therefore P\left(\overline{B}\right)=0.992$

So, probability of $2$ students having same birthday $P\left(B\right)=1-P\left(\overline{B}\right)$

$=1-0.992$

$=0.008$