Question

"$K_{2}O$ is paramagnetic while $K{O}_{2}and{K}_2{O}_2$ are diamagnetic."
Answer whether the above statement is true or false. If true enter 1, else 0

Answer 1

The MO configuration of $O_2^{-}$ is $KK\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_x{)}^2\right(\pi 2p_y{)}^2\left(\pi 2p_z{)}^2\right({\pi }^{\ast }2p_y{)}^2({\pi }^{\ast }2p_z{)}^1$
The MO configuration of $O_2^{2-}$ is $KK\left(\sigma 2s{)}^2\right({\sigma }^{\ast }2s{)}^2\left(\sigma 2p_x{)}^2\right(\pi 2p_y{)}^2\left(\pi 2p_z{)}^2\right({\pi }^{\ast }2p_y{)}^2({\pi }^{\ast }2p_z{)}^2$
The electronic configuration of $O^{2-}$ is $1s^{2}2s^{2}2p_x^{2}2p_y^{2}2p_z^2$
Thus, $K{O}_2$ is paramagnetic (with one unpaired electron in $O_2^{-}$) while $K_{2}Oand{K}_2{O}_2$ are diamagnetic.
Hence, the given statement is false.