-K-a- hydrofluoric acid is 6-9times - 10 - -4 - What is the equilibrium constant K the following reaction-F-H-2Orightleftharpoons HF-OH-1-4times - 10 - -11 -6-9times - 10 - -11 -2-6times - 10 - -9 -8-3times - 10 - -6 -

Question

Toppr Admin · Accepted Answer

Ka for hydrofluoric acid is 6.9×10−4. What is the equilibrium constant K for the following reaction?F−+H2O⇌HF+(OH)−1.4×10−116.9×10−112.6×10−98.3×10−6

$K_{a}$ for hydrofluoric acid is $6.9 \times 10^{- 4}$ . What is the equilibrium constant $K$ for the following reaction?
$F^{-} + H_{2} O ⇌ H F + (O H)^{-}$

$1.4 \times 10^{- 11}$
$6.9 \times 10^{- 11}$
$2.6 \times 10^{- 9}$
$8.3 \times 10^{- 6}$